For a bi-parting slide gate, what is the minimum projected area for the leading edge of receiver guides?

For a bi-parting slide gate, what is the minimum projected area for the leading edge of receiver guides?

• A. 9 square inches
• B. 4 square inches
• C. 12 square inches
• D. 2 square inches

Answer: (A)

The concept here is the size of the face that first meets the sliding leaf—the leading edge of the receiver guides. The projected area is the surface area seen head-on in the direction of travel, and having a minimum amount ensures the edge provides enough contact surface to guide and support the gate reliably, distribute forces, and resist wear or misalignment over many cycles. For bi-parting slide gates, this minimum is specified as 9 square inches. That’s why 9 square inches is the correct choice: it meets the required minimum. A smaller area, like 4 or 2 square inches, would fall short and could lead to binding or faster wear, while a larger area, like 12 square inches, would be more than necessary for the minimum requirement.

The concept here is the size of the face that first meets the sliding leaf—the leading edge of the receiver guides. The projected area is the surface area seen head-on in the direction of travel, and having a minimum amount ensures the edge provides enough contact surface to guide and support the gate reliably, distribute forces, and resist wear or misalignment over many cycles.

For bi-parting slide gates, this minimum is specified as 9 square inches. That’s why 9 square inches is the correct choice: it meets the required minimum. A smaller area, like 4 or 2 square inches, would fall short and could lead to binding or faster wear, while a larger area, like 12 square inches, would be more than necessary for the minimum requirement.